From: [email protected]
To: [email protected]
Subject: RE: How can i get haproxy reload its configuration
Date: Tue, 24 Mar 2015 08:52:20 -0400
> Subject: Re: How can i get haproxy reload its configuration> From: Vincent
> Bernat> Date: 2015-03-24 12:07:34> Message-ID: 87619q61kp.fsf () zoro !
> exoscale ! ch> ⦠24 mars 2015 07:45 -0400, jeff saremi  :> > #!/bin/sh> >
> pidfile=/data/haproxy.pidhaproxy -db \> > -f /haproxy-1.5.8/haproxy.cfg -p
> $pidfile \> > -sf $(cat $pidfile)> The shell does variable substitution
> first, then execute the> line. Hence, $pidfile is expanded to "", not to
> "/data/haproxy.pid". Put> pidfile=... on its own line.> --> I'll burn my
> books.> -- Christopher Marlowe Sorry that was just how my email got through.
> Those are separate lines. So here it is again: #!/bin/sh
> pidfile=/data/haproxy.pid haproxy -db \ -f /haproxy-1.5.8/haproxy.cfg -p
> $pidfile \ -sf $(cat $pidfile) What i'm wondering is how this could have
> ever worked? since the "$(cat $pidfile) and the creation of the $pidfile are
> both on the same line. Is it possible that when the pidfile is concatenated
> for the sake of "-sf" the file does not exist or contains old pids?
So my suspicion around the -sf was correct. Each time i run the haproxy command
I get the following printed on the console:
cat: /data/haproxy.pid: No such file or directory
which seems to be a result of "-sf $(cat $pidfile)" in the command line.
Has anyone successfully done this in practice? is there possibly other ways of
achieving this with having to restart the haproxy process?
thanks
