If what you want is a count you can use the following:
ls ?????????*.m | wc -l
"wc -l" is the "word count" command with the "lines" switch that makes the command only count lines.
Jorge Escala Open Tech Solutions http://www.getopentech.com
On Sep 4, 2004, at 12:50 PM, Nancy Anthracite wrote:
Cool. But, it was ?????????*.m that did the trick! Not what I was trying
to remember, but it worked like a charm!
-----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of m pepper Sent: Saturday, September 04, 2004 12:39 PM To: [EMAIL PROTECTED] Subject: Re: [Hardhats-members] What is that Linux command?
How about ls ????????*.m
----- Original Message ----- From: "Nancy Anthracite" <[EMAIL PROTECTED]> To: "Hardhats" <[EMAIL PROTECTED]> Sent: Saturday, September 04, 2004 11:16 AM Subject: [Hardhats-members] What is that Linux command?
I am looking for any m routines in a directory of VistA routines that areparticular
more than 8 characters before the .m so I can tell if I can use aversion of Linux CD burning software that can't handle more without addinga~1, etc. I recall there is a command that you can use to figure out howmanyfiles in a directory have names of a certain length or more. It is aBournescripting command and I think it involves piping ls to something, but I am
unable to remember how to do it. Can someone help me?
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