The supporting theory is in here: http://www.openmathtext.org/lecture_notes/probability_book2.pdf.
_jim -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of Veech Sent: Thursday, July 20, 2006 5:29 PM To: The Hardware List Subject: Re: [H] Odds calculator wow! that is huge. Can I ask your source for the calculation in case my boss wants to verify the data? ----- Original Message ----- From: "nobozoz" <[EMAIL PROTECTED]> To: "The Hardware List" <[email protected]> Sent: Thursday, July 20, 2006 5:02 PM Subject: RE: [H] Odds calculator > Your chance of drawing 12 white balls consecutively without drawing a > single > red ball is about 1 in 15,879,054. > > Odds_of_success = 1 / [ ((68-0)/(254-0)) * ((68-1)/(254-1)) * ... * > ((68-(n-1))/(254-(n-1)) ] ; where n=12 samples. > > _jim > > > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] Behalf Of Veech > Sent: Thursday, July 20, 2006 1:35 PM > To: The Hardware List > Subject: [H] Odds calculator > > > I need to figure out the odds, or probability, of something happening. > > Say there are 254 ping pong balls are mixed in a bag where 68 of them are > red and the other 186 are white. So, 27% of the balls are red. Someone > who > is blindfolded reaches into the bag twelve times and selects one ping pong > ball each time. What are the odds that all 12 ping-pong balls will be > white? > > can anyone point me to an odds/probability calculator that will help me > establish the percentages on this? Or is anyone adept at this type of > calculation that can answer this question? > > thanks >
