Oh well. Guess I will have to stick to two separate machines :( Thanks for pointing out the errors in my logic.
On 12/21/07, Ben Ruset <[EMAIL PROTECTED]> wrote: > Brian Weeden wrote: > > I wanted to pick everyone's brain a bit about building a > > virtualization machine (vm). > > <snip> > > > Questions I need to get answered before I can pull this off: > > > > - If you install some new software or have another reason to reboot > > one of the VM instances > > can you just restart it and avoid rebooting the whole machine? > > Yes, the VM's are totally independent of each other. They can be brought > up, shut down, created, and destroyed independently of each other. > > > - When you boot up, is there a primary OS that loads and then you run > > the different VMs inside of it or do you boot straight to a VM? > > Unless you're running VMWare ESX ($3000-$4000) you'd boot into an OS and > then load your hypervisor, then boot your VM's. > > > - Can you divvy up the resources for running multiple VMs at once so > > like each gets a GB of RAM and 2 cores? > > You divvy up memory. They all share the CPU. Load put on one VM will > have a negative impact on other VM's and your physical host. I believe > you can set limits in ESX. > > > - Would I need 2 Video cards, one associated with the HTPC VM and one > > associated with the Work/gaming VM? > > There's no concept of assigning physical hardware (beyond a nic) such as > a video card to a VM (at least in the x86 world. You can in Solaris > Logical Domains.) Each VM gets a virtual console, which you connect to > with an app, or in the case of VMWare Server 2.0 beta, a web applet. > > You would not want to run a HTPC in a VM. You'd probably get by making > the system that hosts the hypervisor the HTPC. > > > - If I do need 2 cards, how would that work hardware wise? Never done > > it before in the same box. Do I just get a board with 2 PCI-Express > > slots and slap a card in each? We're not talking about SLI here - but > > two different cards working independently. > > Absolutely will not work the way you describe. > -- Brian Weeden
