Assume an 8 degree incline to the ramp.
The tangent of an angle (in this case 8 degrees) equals "the rise divided by
the run" or y/x.
In this example, the rise is either 1 ft or 3 ft, so,
tan(8 degrees) = rise_ft / run_ft = y_ft / x_ft
or ...
x_ft = (1 ft) / tan(8 degrees) = (1 ft) / (0.140541) = (7.11537 ft)
and ...
x_ft = (3 ft) / tan(8 degrees) = (3 ft) / (0.140541) = (21.3461 ft)
y
/y
/ y
/ y
h/ y
/ y
/ y
/ y
/) y
xxxxxxxxx0
In the above drawing, x == y and the triangle is 9 y's rise by 9 x's run.
The angle /) is 45 degrees (although it doesn't look right due to font
dimensions),
and tan(45 degrees) = 1.0 = 9/9.
If you need the length of the inclined path (h = hypotenuse), use
Pythagarus' theorem:
h^2 = x^2 +y^2
or ...
h = (x^2 +y^2)^(1/2) = 21.5559 ft
or ... [sin(8 degrees) = h / rise_ft]
h = 1 ft / sin(8 degrees) = 7.18530 ft ; sin(8 degrees) = 0.139173
h = 3 ft / sin(8 degrees) = 21.5559 ft ; sin(8 degrees) = 0.139173
hth,
Jim
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Harvey Best
Sent: Sunday, July 13, 2008 9:33 AM
To: Alt Cpu
Subject: [H] OT Inclined planes
As a distraction form my network backup problems, a friend called me and
asked this question. I am using google now to see if I can find the formula.
Here is his question:This is about Inclined Planes.....
How long does a ramp have to be to raise a plane 8 degrees
from horizontal to a hight of one foot...
Also would like the length
to a hight of 3 feet, at the same degree of incline, if you can do it...
Any help with formula and answer greatly appreciated.
Why do I get myself in these situations. lol
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