On 11/20/2012 01:57 PM, Greg London wrote:
>
> Ah, that put me in the right direction.
>
> main.cpp looks like this:
> #################################
> #include <iostream>
> using namespace std;
>
> #include "logger.h"
>
> int main ()
> {
> Note("hello world\n");
> return 0;
> }
>
>
> logger.h looks like this:
> ##################################
> #include <iostream>
> using namespace std;
>
> extern void Note(string msg);
>
>
> logger.cpp looks like this:
> ##################################
> #include <iostream>
> using namespace std;
>
> void _say(string msg){
> cout<<msg;
> }
>
> void Note(string msg){
> _say("Note: "+msg);
> }
>
>
>
>
>
> my compile command looks like this:
> #######################################
> g++ logger.cpp main.cpp
>
>
>
>
> This looks like quite lovely code now.
>
> Thanks!
>
Almost perfect. I would make a few minor changes.
void _say(const string msg&){
cout<<msg;
}
void Note(const string msg&){
_say("Note: "+msg);
}
Minor efficiencies. In your code in when note() is called the string is copied
so msg is a copy of the input. In _say("Note: "+msg);
you are creating a new string, but that string is also copied. Setting up a
call by reference saves 2 copies in this case. The compiler can optimize the
_say function to where the call by reference does not matter, but not the
note() function which is external.
--
Jerry Feldman <[email protected]>
Boston Linux and Unix
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