Danny Gratzer wrote > Isn't the product check actually redundant? re-reading the requirements we > could just define a = 1 and b = x. Maybe I'm misunderstanding though.
I'm not sure. As I understand the requirement, the squer of y should not be greater than 1000. But anyway, without this condition it doesn't work yet Do you have any idea, what is wrong with it now? -- View this message in context: http://haskell.1045720.n5.nabble.com/list-comprehension-doesn-t-work-tp5730158p5730168.html Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
