At 2001-11-12 18:06, Jesper Louis Andersen wrote: >mean :: (Fractional a) => [a] -> a >mean l = (sum l)/ fromIntegral (length l) > >Which imposes a type constraint (of course). My problem is, that i >cannot ``let go'' of this constraint.
... >main :: Fractional Int => IO () It sounds like you're trying to use your 'mean' function on Ints. Int is not a Fractional type (unless you make it one), and so '/' isn't defined on it. What's "mean [3::Int,4::Int]"? It can't be "3.5::Int" because 3.5 is not an integer and so not an Int. -- Ashley Yakeley, Seattle WA _______________________________________________ Haskell-Cafe mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/haskell-cafe
