On Tue, Mar 04, 2003 at 12:25:01PM +1100, Andrew J Bromage wrote: > Or, even better, if you didn't multiply stuff that you're just going > to divide out in the first place.
I had thought of that before, and used a simple comb m n = product [m, m-1 .. m-n+1] / fact (m-n) but the unmemoized product proved to be slower than the original. This looks rather different, though. :) -xx- Damien X-) _______________________________________________ Haskell-Cafe mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/haskell-cafe
