Re: determining if a int is a power

[Hamilton Richards]

Also note that

	if x then True else False

is just a verbose way of writing

	x

At 2:51 PM -0800 11/7/03, Hal Daume III wrote:
try "floor (sqrt (fromIntegral n))"

On Fri, 7 Nov 2003 [EMAIL PROTECTED] wrote:

 hello all,

 im new to haskell and have to do some excersises. Well i ran into 
this problem. I have to determin if a list of int's contains a int 
that is a power. So i have been trying using "any" with a helper 
function which return a Bool if the int is a power and applying 
that to the list. I think that this aproach should work.
 Anyway the problem im having is in the helper function. I have 
been trying this:
 isPower n =
	let powerF = floor(sqrt(n)) in
    	if (powerF*PowerF == n)
		then True
 >		else False
[...]
--
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Hamilton Richards, PhD           Department of Computer Sciences
Senior Lecturer                  The University of Texas at Austin
512-471-9525                     1 University Station C0500
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