>to be [] in each case. ahh but in this example:
f :: [Int] -> [Bool] f (i:is) = even i : f is f [EMAIL PROTECTED] = e e is an empty list of Ints not an empty list of Bools! you mean: f :: [Int] -> [Bool] f (i:is) = even i : f is f _ = [] Keean. _______________________________________________ Haskell-Cafe mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/haskell-cafe
