I have a lot of code of the form
foo {bar = fn $ bar foo}Is there a more concise syntax? I am thinking the record equivalent of C's foo+=5...
I imagine there is some operator that does this e.g.
foo {bar =* fn}But I don't know what it is...
-Alex-
______________________________________________________________ S. Alexander Jacobson tel:917-770-6565 http://alexjacobson.com _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
