If he really wanted to use a case-expression, he could write it this way:
f x = case x of
False -> 0
True -> 1
--Ham
At 1:02 PM +0100 2005/1/27, Henning Thielemann wrote:
On Thu, 27 Jan 2005 [EMAIL PROTECTED] wrote:
Can a kind soul please enlighten me on why f bit0 and f bit1 both return 0?
> bit0 = False > bit1 = True > f x = case x of > bit0 -> 0 > bit1 -> 1
If you compile with 'ghc -Wall' GHC should report that the identifier 'bit0' in the case expression shadows the global 'bit0' identifier. What you want to do is:
f x = if x == bit0 then 0 else 1
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