On Wed, 18 May 2005, Bjorn Lisper wrote:

forall (i,j) -> i + j, a Vandermonde matrix

This does not look like a Vandermonde http://mathworld.wolfram.com/VandermondeMatrix.html

If you take reciprocals you obtain almost a Hilbert matrix.
 http://mathworld.wolfram.com/HilbertMatrix.html
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