Scott Michel <[email protected]> wrote:

> I might be missing something in translation, but if I understand
> Takayuki's message's intent, everything needs to be calculated because
> the C-based FFTW library is called (eventually). Laziness doesn't
> really have an impact.
>
> The choice of underlying data structure and whether FFTW wisdom is
> used clearly has a significant impact.

If the Haskell wrapper library is a thick enough, lazy layer around
FFTW, the size of the result vector may not at all depend on any FFTW
computation.

Again, I have no experience at all with FFTW or any Haskell bindings to
it.  This is just a general remark that is worth keeping in mind.


Greets,
Ertugrul

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