>From the point of view of the language, Message () and Message Int and
Message Player are all completely distinct types and may have different
behavior--there's no way for it to "know" that they all have the same
representation that only contains a String.
The derived Typeable instance for "Message m" is really a derived instance
of "Typeable1 Message" along with the generic instance "(Typeable1 f,
Typeable a) => Typeable (m a)" in Data.Typeable.
So you need to specify the type of message you want, or drop the type
parameter from Message.
A simpler answer, though, would just be to put the functions in the
typeclass.
class Event e where
viewEvent :: e -> IO ()
instance Event Player where
viewEvent (Player a) = putStrLn $ show a
instance Event (Message m) where
viewEvent (Message s) = putStrLn s
In this case, the instance makes it clear that the type parameter is
irrelevant and puts no constraints on it. And the type of viewEvent is
exactly the same as you were asking for: Event e => e -> IO ().
-- ryan
On Mon, Sep 10, 2012 at 3:06 PM, Corentin Dupont
<corentin.dup...@gmail.com>wrote:
> Hi Stephen,
> I wasn't aware of Data.Dynamic.
> I tried:
>
> *viewEvent :: Dynamic -> IO ()
> viewEvent event = do
> case fromDynamic event of
> Nothing -> return ()
>
> Just (Message s) -> putStrLn $ show s
> *
>
> But still got the same error (Ambiguous type variable `t0' in the
> constraint: (Typeable t0) arising from a use of `fromDynamic')...
>
> Best,
> Corentin
>
>
>
> On Mon, Sep 10, 2012 at 11:33 PM, Stephen Tetley <stephen.tet...@gmail.com
> > wrote:
>
>> Whilst dynamic typing isn't idiomatic for Haskell, it seems like
>> you've decided you want it. So why not use Data.Dynamic rather than
>> roll you're own dynamic typing with Typeable?
>>
>
>
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> Haskell-Cafe@haskell.org
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>
>
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