Well, I do need to have access to all those thread handles.
On Dec 6, 2005, at 2:43 PM, Maarten Hazewinkel wrote:
I apologise if this doesn't make sense (I'm fairly new to Haskell),
but
wouldn't a single shared counter be sufficient for this?
Increment for each child launched.
Decrement by each finished child.
When it's back down to zero, you're done.
--
http://wagerlabs.com/
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