Re: [Haskell-cafe] Existentially-quantified constructors, Eq and Show

[Joel Reymont]

On Dec 8, 2005, at 12:09 AM, John Meacham wrote:

if you are okay with a being an argument then

data State a
    = Start
    | Stop
    | State a
   deriving(Show,Eq)

will do what you want I believe.

This does the trick! Thank you!

--
http://wagerlabs.com/





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