You can't do this in Haskell, if you try to type the function carefully, you'll know the reason.
Shiqi On 5/18/06, Aditya Siram <[EMAIL PROTECTED]> wrote:
I am trying to write a function 'applyArguments' which takes a function and a list and recursively uses element each in the list as an argument to the function. I want to do this for any function taking any number of arguments. applyArgument f (arg) = f arg applyArgument f (arg:args) = applyArgument (f arg) args This has failed in Hugs, so my question is: Can I conceptually do this? If so, what is the type signature of this function? Deech _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
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