Well, bind is extracting an 'a'. I clearly see a '\ a -> ...'; it
getting an 'a' so it can give that to g. Granted, the extraction is
very convoluted, but it's there.
-- Lennart
On Sep 2, 2006, at 19:44 , Udo Stenzel wrote:
Benjamin Franksen wrote:
Sure. Your definition of bind (>>=):
...
applies f to something that it has extracted from m, via
deconstructor
unpack, namely a. Thus, your bind implementation must know how to
produce
an a from its first argument m.
I still have no idea what you're driving at, but could you explain how
the CPS monad 'extracts' a value from something that's missing
something
that's missing a value (if that makes sense at all)?
For reference (newtype constructor elided for clarity):
type Cont r a = (a -> r) -> r
instance Monad (Cont r) where
return a = \k -> k a
m >>= g = \k -> m (\a -> g a k)
Udo.
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