Can someone explain to me, given that (a) I'm not particularly expert
at maths, (b) I'm not particularly expert at Haskell, and (c) I'm a
bit fuzzybrained of late:
Given that _|_ represents in some sense any computation not
representable in and/or not consistent with Haskell, why/how is
reasoning about Haskell program behavior in the presence of _|_ *not*
like reasoning about logic behavior in the presence of (p^~p)->q?
--
brandon s. allbery [linux,solaris,freebsd,perl] [EMAIL PROTECTED]
system administrator [openafs,heimdal,too many hats] [EMAIL PROTECTED]
electrical and computer engineering, carnegie mellon university KF8NH
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