On Jan 26, 2007, at 4:56 PM, Sean McLaughlin wrote:
Hello,
I'm trying to write a simple function to time an application.
-- this doesn't work
time f x =
do n1 <- CPUTime.getCPUTime
let res = f x in
do n2 <- CPUTime.getCPUTime
return (res,n2 - n1)
On a function that takes 8 seconds to complete, returns
(True,46000000)
Remember that Haskell is lazy -- res won't be evaluated until it is
forced. See the evaluate function in Control.Exception to force a
value in the IO monad.
Spencer Janssen
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