geniusfat wrote:
hi dear haskell lover ;)
what I want to do is simply this:
select3 :: [a] -> [(a, a, a)]
and how can it be done efficiently?
thanks in advance!
What, as in
select3 [1..10] ->
[(1,2,3),(2,3,4),(3,4,5),(4,5,6),(5,6,7),(6,7,8),(7,8,9),(8,9,10)]
?
How about like this:
select3 = map (\[x,y,z] -> (x,y,z)) . filter ((2 <) . length) . take 3
. tails
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