On 29/05/07, Daniel McAllansmith <[EMAIL PROTECTED]> wrote:
Just in case there was some sort of miscommunication, the actual answer to your question is (/=) :: a -> a -> Bool, as Neil said.
Almost, (/=) :: Eq a => a -> a. (Just for completeness.) -- -David House, [EMAIL PROTECTED] _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
