On Wed, Jul 04, 2007 at 04:20:20PM -0700, Michael Vanier wrote: > I'm sure this has been done a hundred times before, but a simple > generalization of foldl just occurred to me and I wonder if there's > anything like it in the standard libraries (I couldn't find anything). > Basically, I was trying to define the "any" function in terms of a fold, > and my first try was this: > > > any :: (a -> Bool) -> [a] -> Bool > > any p = foldl (\b x -> b || p x) False > > This is inefficient, because if (p x) is ever True the rest of the list is > scanned unnecessarily.
Rather than create a new escape fold, it's much easier, simpler, and faster just to use a right fold: any p = foldr (\x b -> p x || b) False That will short-ciruit well by laziness, and is made tailrecursive by same. Stefan _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
