Jon Harrop wrote: > If you have a boolean-or expression: > > a || b > > will "a" be evaluated before "b" in Haskell as it is in other languages?
Yes, although the meaning of the phrase "evaluated before" is a bit tricky in a lazy language, so it's probably better to state it with denotational semantics alone: _|_ || b = _|_ Maybe you also want to know whether the second argument "is evaluated". This is answered by True || _|_ = True False || _|_ = _|_ Regards, apfelmus _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
