rewrite *p++=*q++ in haskell?
*p = *(p+1) ; *q = *(q+1)
If that's true then GCC has gone insane, because they are completely different.
Of course you are right, I just observed at the wrong place..., sorry for that.
Though, as any C programmer knows, you really should be using memcpy()
I like to hear that you would reject it either. /BR -- -- Mirko Rahn -- Tel +49-721 608 7504 -- --- http://liinwww.ira.uka.de/~rahn/ --- _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
