On 06/09/07, Axel Gerstenberger <[EMAIL PROTECTED]> wrote: > Thanks to all of you. The suggestions work like a charm. Very nice. > > I still need to digest the advices, but have already one further > question: How would I compute the new value based on the 2 (or even > more) last values instead of only the last one? > > [ 2, 3 , f 3 2, f((f 3 2) 3), f ( f((f 3 2) 3) f 3 2)), ...]
foo = 2 : 3 : zipWith f (drop 1 foo) foo There's also zipWith3 etc. for functions with more arguments. -- Sebastian Sylvan +44(0)7857-300802 UIN: 44640862 _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
