It's probably \oplus then.
The font size according to my trusty screen reader is 11 point which
is not particularly large. Still, if anybody else finds it annoying
I'll reduce it to 9pt.
Paul
At 13:21 19/09/2007, you wrote:
This looks like foldr, specifically:
f = foldr (.) v
so really, there's no way of telling what the operator could be, other
than that:
(.) :: a -> b -> b
where
f :: [a] -> b
v :: b
BTW, I find that most of your emails are in a very large font size. Do
other people notice this? It's not very nice to read. Gmail's 'Show
Original' feature tells me that the HTML version of your message
contains <font size=3> near the start.
On 19/09/2007, PR Stanley <[EMAIL PROTECTED]> wrote:
> Hi
> Here's another one:
> f [] = v
> f (x:xs) = x . f xs
> The "." is supposed to denote a generic operator - f [] maps to some
> value v and applied to non-empty list applies head to ? operator.
> Thanks, Paul
>
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