G'day all.
Quoting PR Stanley <[EMAIL PROTECTED]>:
Fully lazy? Can you elaborate please?
Sure. that code again:
test1 = \n _ -> 1+n
test2 = \n -> let x = n+1 in \_ -> x
Suppose we have:
f g x = g x + g x
And we try two options:
f (test1 4) 3
f (test2 4) 3
In the first case, (1+4) will be evaluated twice. In the second case, it
will only be evaluated once.
Cheers,
Andrew Bromage
_______________________________________________
Haskell-Cafe mailing list
[email protected]
http://www.haskell.org/mailman/listinfo/haskell-cafe
