> tfoldr (-) 1 [4,3] > = 4-3-(-1) > = 2 Erm? You mean "foldr"?
foldr (-) a [x,y,z,t,w] == x - (y - (z - (t - (w - a)))) So, foldr (-) 1 [4,3] == 4 - (3 - 1). > A similar thing happens with foldr (/) 2 [8,2] = 8.0 8/(2/2) = 8/1 = 8 > I thought foldr \oplus v [] = v Yeah, that's right. _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
