Hi reverse = foldl (xs x . x:xs) [] (xs ++ ) = foldl (\ys y -> ys ++ [y]) xs If I were to define reverse with foldl I would do it this way: reverse = foldl (\x -> \xs -> xs:x) []
Any idea what the first code frag is suposed to achieve? Thanks, Paul _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
