It's: f $! x = x `seq` f x
That is, the argument to the right of $! is forced to evaluate, and then that value is passed to the function on the left. The function itself is not strictly evaluated (i.e., f x) I don't believe. Justin _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
