Hello Andrew, Sunday, November 18, 2007, 10:04:15 PM, you wrote:
> Wait, so... f x = ... g = f $! x > and f !x = ... g = f x > mean the same thing? in both cases, x is evaluated before evaluating body of x. but of course, this happens only at the moment when value of (f x) itself is required -- Best regards, Bulat mailto:[EMAIL PROTECTED] _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
