[EMAIL PROTECTED] writes: > increment b = b + 1
This is also called 'succ' (for successor). > main = do let b = 0 > let c = randomRIO (1,2) > until (c == 1) increment b > return b > ERROR "StPetersburg.hs":8 - Type error in application > *** Expression : until (c == 1) increment b > *** Term : c == 1 > *** Type : Bool > *** Does not match : Int -> Bool Prelude> :t until until :: (a -> Bool) -> (a -> a) -> a -> a So until wants a function from a something to a boolean, but you are giving it (c==1) which is just a boolean. More generally, I think you should solve this in a more functional style, perhaps using randomRs to get a list of coin tosses, and take what you need from that. -k -- If I haven't seen further, it is by standing in the footprints of giants _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
