> Note that your h does not differentiate between f and g (in fact, it > does not investigate them at all), the only thing you can do with f, > g, (h f), and (g f) is apply them. Accordingly, it's a fine Haskell > definition.
Errr... (h g), not (g f) _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
