cristi: > On Thu, 10 Jan 2008 10:22:03 +0200, Mitar <[EMAIL PROTECTED]> wrote: > > >Hi! > > > >Why is 0/0 (which is NaN) > 1 == False and at the same time 0/0 < 1 == > >False. This means that 0/0 == 1? No, because also 0/0 == 1 == False. > > > >I understand that proper mathematical behavior would be that as 0/0 is > >mathematically undefined that 0/0 cannot be even compared to 1. > > > >There is probably an implementation reason behind it, but do we really > >want such "hidden" behavior? Would not it be better to throw some kind > >of an error? > > NaN is not 'undefined' > > (0/0) /= (0/0) is True > (0/0) == (0/0) is False > > You can use these to test for NaN.
You can also use isNaN :) Prelude> isNaN (1/0) False Prelude> isNaN (0/0) True -- Don _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe