Wolfgang Jeltsch <[EMAIL PROTECTED]> schrieb: > > However, the fact that (0 / 0) == (0 / 0) yields False is quite shocking. It > doesn?t adhere to any meaningful axiom set for Eq. So I think that this > behavior should be changed. Think of a set implementation which uses (==) to > compare set elements for equality. The NaN behavior would break this > implementation since it would allow for sets which contain NaN multiple > times.
You forget, that the intention of NaN is denial of membership of any set of numbers. -- Dipl.-Math. Wilhelm Bernhard Kloke Institut fuer Arbeitsphysiologie an der Universitaet Dortmund Ardeystrasse 67, D-44139 Dortmund, Tel. 0231-1084-257 PGP: http://vestein.arb-phys.uni-dortmund.de/~wb/mypublic.key _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
