On Apr 1, 2008, at 17:07 , PR Stanley wrote:
I'm beginning to wonder if I fully understand the right associativity rule for the -> operator.
Read a parenthesized unit as an argument: > (a -> (b -> (c -> d))) (((f 1) 2) 3) > (((a -> b) -> c) -> d) (f (1 (2 3))) -- brandon s. allbery [solaris,freebsd,perl,pugs,haskell] [EMAIL PROTECTED] system administrator [openafs,heimdal,too many hats] [EMAIL PROTECTED] electrical and computer engineering, carnegie mellon university KF8NH _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe