Hello,
> > $ pointfree "\xs -> foldl' (+) 0 xs / fromIntegral (length xs)"
> > ap ((/) . foldl' (+) 0) (fromIntegral . length)
>
This will have the same space usage as the pointed version. You can see
this by looking at the monad instance for ((->) r):
instance Monad ((->) r) where
return = const
f >>= k = \ r -> k (f r) r
-Jeff
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