"Lauri Oksanen" <[EMAIL PROTECTED]> writes: > Thanks for help. I did some tests with UArray and it does the trick. > The problem remaining is, how to implement UArray Int (Double, Double, > Double)?
As (UArray Int Double, UArray Int Double, UArray Int Double). Or as UArray Int Double, but with a specialized lookup function: mylookup array index = (array!3*index, array!3*index+1, array!3*index+2) I guess it would be possible to have UArray Int (# Double, Double, Double #) - packing all three Doubles unboxed into the array, but I've no clue how to go about automating that. -k -- If I haven't seen further, it is by standing in the footprints of giants _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
