On Thu, 2008-10-16 at 11:41 -0700, Robert Greayer wrote:
> --- On Thu, 10/16/08, Jonathan Cast <[EMAIL PROTECTED]> wrote:
>
> > But I can't say new HashSet<?>()?
> >
> No... but you can say 'new HashSet<T>()' where T is a type variable,
> and then put a value of type T into your set, which is probably
> generally what you want. HashSet<?> is a set of unknown (at compile
> time) element type. It is not safe to put any element into such a
> set. Consider:
>
> void wrong(List<?> foo, List<?> bar) {
> foo.add(bar.get(0)); // illegal... but if it weren't...
> }
So if I say
void wrong(List<?> foo, List<?> bar)
I get two /different/ type variables implicitly filled in?
If I declare a generic class, and then have a method, is there a way, in
that method's parameter list, to say `the type parameter that was
supplied when my class was instantiated'?
> ...
> List<Integer> x = ...;
> List<String> y = ...;
> wrong(x, y); // then this would put an String into a list of ints...
Yikes. So, in this instance, the difference between Haskell and Java
is: if you want to disallow that call to wrong, in Haskell you can...
> ---
> Perhaps there was confusion over what you meant by 'conjure up a value
> of an unknown type'... you can't explicitly instantiate a
> parameterized class with a wildcard type variable (e.g. new
> HashSet<?>).
Right. Which is a logical consequence of parametric polymorphism.
> However, you can conjure up an instance of any class for which you
> have a Class object handy, provided it is non-abstract and has public
> constructors, and then assign it to a variable with a wildcard in its
> type.
(Which is a logical consequence of non-parametric polymorphism,
concerning which: yikes!)
jcc
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