yep ... that is exactly what I meant!! so can I use more $'s or must I use parens (as you did) to disambiguate?
Vasili On Mon, Jan 5, 2009 at 12:18 PM, Ross Mellgren <rmm-hask...@z.odi.ac> wrote: > Did you mean: > B.intercalate (B.intercalate ByteString [ByteString]) [ByteString] > > ($) applies all the way to the right, so you were giving the inner > intercalate two lists of ByteString. > > -Ross > > > On Jan 5, 2009, at 1:17 PM, Galchin, Vasili wrote: > > Hi Max, > > That is what should happen .... The inner B.intercalate will produce > the ByteString to be used by the B.intercalate. ?? > > Vasili > > On Mon, Jan 5, 2009 at 12:13 PM, Max Rabkin <max.rab...@gmail.com> wrote: > >> 2009/1/5 Galchin, Vasili <vigalc...@gmail.com>: >> > Hello, >> > >> > I have the following: >> > >> > B.intercalate $ B.intercalate >> > ByteString >> > [ByteString] >> > [ByteString] >> > >> > I get a type error with this. If I comment out the 2nd >> B.intercalate >> > and the third parameter I get no type errors. >> >> B.intercalate needs a ByteString and a list of ByteStrings. Two >> B.intercalates need two ByteStrings and two lists of ByteStrings. >> >> --Max >> > > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe > > >
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