On Mon, Jan 12, 2009 at 6:06 PM, Robin Green <gree...@greenrd.org> wrote: > The fix-style equivalent to your repeat above, would be something like > this: > > repeat x = fix $ \me -> x ::: me
Interesting. Your repeat and mine are compiled to the same code: Data.Stream.repeat :: forall a_aVi. a_aVi -> Data.Stream.Stream a_aVi Data.Stream.repeat = \ (@ a_a2lT) (x_aZ6 :: a_a2lT) -> letrec { repeat_x_s50K :: Data.Stream.Stream a_a2lT repeat_x_s50K = Data.Stream.::: @ a_a2lT x_aZ6 repeat_x_s50K; } in repeat_x_s50K Bas _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe