2009/3/11 R J <[email protected]>: > 2. I believe that the reverse implementation--namely, implementing foldr in > terms of foldl--is impossible. What's the proof of that?
That's correct. Consider their behaviour on infinite lists. --Max _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
