> I've used a similar function myself, but why write it in such a complicated
> way? How about
>
> lfp :: Eq a => (a -> a) -> a -> a
> lfp f x
> | f x == x = x
> | otherwise = lfp f (f x)
I've used a similar function too, but your version computes f x twice
per iteration, I wrote mine as:
fix :: Eq a => (a -> a) -> a -> a
fix f x = if x == x2 then x else fix f x2
where x2 = f x
I find this fix much more useful than the standard fix.
Thanks
Neil
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