Hello
What do you think of this? There is perhaps a recursive call that should be
made tail recursive but it seems to work.
The 'group' function takes the list of pairs as input and outputs a list of
maps from key to sums.
The nth element of the list of maps corresponds to the grouping applied for
the elements 0....n of the input list of pairs. Thus, that also works on
infinite list.
Unless I am missing sth...
import Data.Map (Map)
import qualified Data.Map as Map
group :: [(Int,Int)] -> Map Int Int -> [Map Int Int]
group [] amap = []
group ((k, v):t) amap = newmap : group t newmap
where
newmap = (Map.insertWith (+) k v amap)
l = [(1,1), (2,10), (1,2), (2,11), (1,3), (2,12)]
r = group l Map.empty
rr = take 2 r
li = concat [ [(1,i), (2, 10*i)] | i <- [0..] ]
ri = group li Map.empty
rri = take 20 ri
Regards
J-C
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