Jason, Thank you for your answer. I haven't found unliterate capability in GHC, but I found unlit function in Distribution.Simple.PreProcess.Unlit, which do the things I needed.
Best regards, Vasyl 2009/4/14 Jason Dagit <[email protected]>: > On Mon, Apr 13, 2009 at 3:37 PM, Vasyl Pasternak > <[email protected]> wrote: >> Hello, >> >> Are there ability to parse literate haskell source with >> Language.Haskell.Parser, or maybe >> there is some tool, which converts .lhs files to .hs ? > > You can ask GHC to remove the literate bits. I think the command is > called 'unlit' but check the GHC manual to be sure. > > Jason > _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
