Keep in mind that using lists for your parameters means you lose static guarantees that you've passed the correct number of arguments to a function (so you could crash at runtime if you pass too few or too many parameters to a function).
On Wed, May 6, 2009 at 11:41 AM, Nico Rolle <nro...@web.de> wrote: > super nice. > best solution for me so far. > big thanks. > regards > > 2009/5/6 Victor Nazarov <asviraspossi...@gmail.com>: >> On Tue, May 5, 2009 at 8:49 PM, Nico Rolle <nro...@web.de> wrote: >>> >>> Hi everyone. >>> >>> I have a problem. >>> A function is recieving a lambda expression like this: >>> (\ x y -> x > y) >>> or like this >>> (\ x y z a -> (x > y) && (z < a) >>> >>> my problem is now i know i have a list filled with the parameters for >>> the lambda expression. >>> but how can i call that expression? >>> [parameters] is my list of parameters for the lambda expression. >>> lambda_ex is my lambda expression >>> >>> is there a function wich can do smth like that? >>> >>> lambda _ex (unfold_parameters parameters) >> >> Why not: >> >> lam1 = \[x, y] -> x > y >> lam2 = \[x, y, z, a] -> (x > y) && (z < a) >> >> doLam :: Ord a => ([a] -> Bool) -> [a] -> Bool >> doLam lam params = lam params >> >> So, this will work fine: >> >> doLam lam1 [1, 2] >> doLam lam2 [1,2,3,4] >> >> -- >> Victor Nazarov >> > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe > _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
