David Menendez wrote:
If you don't need code that's polymorphic between Foobar HasZoo and Foobar NoZoo, you could just newtype Foobar and only export smart constructors.
Unfortunately I want to be able to print both of them out. (After all, the printing algorithm is identical whether Zoo is present or not - except that if Zoo isn't there, you don't need to handle Zoo!)
Nice idea though. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
